An electtron and a photon have same wavelength . If `p` is the moment of electron and `E` the energy of photons, the magnitude of `p//E` in S I unit is

Options

A. `6.64xx10^(-34)`
B. `3.33xx10^(-9)`
C. `9.1xx10^(-31)`
D. `3xx10^8`

Answer

B

Explanation

`lamda = h/p` for the electron
`thereforeo p = h/lamda` (from de broglie equation) ….(1)
and of the photon , `E = hv = (hc)/(lamda) " "…(2)`
Both of them have the same wavelength.
`therefore P/E = h/lamda xx lamda/(hc) = 1/c`
`=(1)/(3xx10^8) = 3.33xx10^9`