The binding energy per nucleon of `O^16` is `7.97 MeV` and that of `O^17` is `7.75 MeV`. The energy (in MeV) required to remove a neutron from `O^17` is.

Options

A. 3.64
B. 3.52
C. 7.86
D. 4.23

Answer

D

Explanation

The nuclear reaction is `O^17 to O^16 + ""_0n^1`
`""_n^1` = represents the neutron.
`therefore` Energy required
= Binding energy of `O^17 - B.E. of O^16`
`=17xx7.75-16xx7.97`
` = 131.75 - 127.52`
`therefore E = 4.23 MeV`