In the given reaction
`._z X^A rarr ._(z+1)Y^A rarr ._(z-1) K^(A - 4) rarr ._(z-1) K^(A - 4)`
Radioactive radiations are emitted in the sequence.

Options

A. `gamma, beta, alpha`
B. `gamma, alpha, beta`
C. `alpha, beta, gamma`
D. `beta, alpha, gamma`

Answer

D

Explanation

In `""_ZX^A to ""_(Z+1)Y^A` , charge is increased by 1 but A remains constant.
`therefore " One " beta` particle is emitted in the reaction
In `""_(Z+1) Y^A to ""_(Z -1)K_1^(A-4)`
There is an emission of an `alpha` particle as Z is decreased by 2 and A is decreased by 4 and in the reaction
`""_(Z-1)K_1^(A-4) to ""_(Z-1)K_2^(A-4)` there is no change in A and Z .Hence there is an emission of `gamma` radiation.
`therefore` The sequence of emission is `beta, alpha, gamma`