The standard Gibb's free energy change, `DeltaG^(@)` is related to equilibrium constant, kp as

Options

A. `K_(p)=-RTInDeltaG^o`
B. `K_(p)=[e/(RT)]^(DeltaG^o)`
C. `K_(p)=-(DeltaG)/(RT)`
D. `K_(p)=e^(-DeltaG^o//RT`

Answer

D

Explanation

`Delta G^@ =- RT ln K_p or ln K_p =- (Delta G^2)/(RT)`
or `K_p = e^(-Delta G^0 //RT`