2 moles of an ideal gas expanded isothermally from `2.5 xx 10^(-3) m^(3) " to "7.55 xx 10^(-3) m^(3)` against a constant external pressure of `5 xx 10^5 Nm^(-2)` The work done in the process is

Options

A. `-2.525 kJ`
B. `-0.2525 kJ`
C. `-0.2525 kJ`
D. `-2.525 J`

Answer

A

Explanation

`W= - P Delta V = 5 xx 10^5 (7.55 - 2.5) xx 10^(-3)`
`=-2525 j = -2.525 kj`