`1` mole of gas occupying `3` litre volume is expanded against a constant external pressure of `1` atm to a volume of `15` litre. The work done by the system is:

Options

A. `-1.216 xx 10^3 J`
B. `-12.16 xx 10^3 J`
C. `-121.6 xx 10^3 J`
D. `-12.16 xx 10^3 J`

Answer

A

Explanation

`W_("irr")= -P_("ext")(V_2 -V_1)`
`=- 1 xx (15-3)= 12 L atm.`
`=- 12 xx 101. 352 J= -12165 `
` =- 12 xx 101. 325 j =- 12165 `
`=- 1.215 xx 10^3 J `