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For a gaseous reaction, `A(g)+3B(g)to3C(g)+3D(g),DeltaU` is 17 kcal at `27^(@)C`. Assuming `R=2cal" "K^(-1)mol^(-1)`, the value of `DeltaH` for the above reaction is:

A

`15.8 " kcal " `

B

`16.4 " kcal " `

C

`18.2 " kcal " `

D

`20.0 " kcal " `

Text Solution

Verified by Experts

The correct Answer is:
C

`Delta H = Delta U+ DeltaRT " " therefore Delta n =2 `
`Delta H = 17 +(2 xx 2 xx 10^(-3) xx 300)=18.2 kcal `
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