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Given the reaction at 967^(@)C and 1 atm...

Given the reaction at `967^(@)C` and `1 atm`.
`CaCO_(3)(s)hArrCaO(s)+CO_(2)(g)`
`DeltaH=176 kJ mol^(-1)`, then `DeltaE` equals

A

160.0 kJ

B

165.6 kJ

C

186.4kJ

D

180.0 kJ.

Text Solution

Verified by Experts

The correct Answer is:
B

`Deltan =1 -0 =1 , Delta U = Delta H + Delta n _g RT`
`=+176 -1 xx (8.314)/(1000) xx 1240 = 165.6 kj`
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