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The heat of combustion of sucrose (C(12)...

The heat of combustion of sucrose `(C_(12)H_(22)O_(11))` is `1350 kcal//mol`. How much of heat will be liberated when `17.1 g` of sucrose is burnt ?

A

67.5 kcal

B

13.5 kcal

C

40.5 kcal

D

25.5 kcal

Text Solution

Verified by Experts

The correct Answer is:
A
Heat evolved from 1 mole of suroce (342 g) = 1350 kcal
Heat evolved from 17.1 g of sucrose
`=(1350)/(342) xx 17.41 = 67.5 ` kcal.
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