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When 12.0 g of carbon reacted with limit...

When 12.0 g of carbon reacted with limited quantity of oxygen, 57.5 kcal of heat was produced, calculate the number of moles of CO produced `(Delta_(f)H(CO_(2))=-94.5 cal, Delta_(f)H(CO)= -21.41kcal.`

A

0.54 mol

B

0.50 mol

C

0.64 mol

D

0.74 mol

Text Solution

Verified by Experts

The correct Answer is:
B

`12 g C =1` mole . Suppose CO product = x moles.
Then `CO_2` produced = (1+x) mole
`therefore x (-21.41)+(1-x) (-94.05)=- 57.5 `
This on solving gives x = 0.50 mole.
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