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Given that - 2C(s)+2O(2)(g)rarr 2CO(2)...

Given that -
`2C(s)+2O_(2)(g)rarr 2CO_(2)(g) Delta H = -787 KJ`
`H_(2)(g)+ 1//2O_(2)(g)rarr H_(2)O(l) Delta =-286 KJ`
`C_(2)H_(2)(g)+(5)/(2)O_(2)(g)rarr H_(2)O(l) Delta H=-1310 KJ`
Heat of formation of acetylene is :-

A

`-1802 KJ`

B

`+1802 KJ`

C

`-800 kJ`

D

`+228 KJ`

Text Solution

Verified by Experts

The correct Answer is:
D
Aim `2C_(s) + H_(2(g)) rarr C_2 H_2(g)`
Opeate (i)+(ii)-(iii).We get
`Delta H=-787 +(-286)-(-1301)=+ 228 kJ.`
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