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A person requires 2870kcal of energy to ...

A person requires `2870kcal` of energy to lead normal daily life. If heat of combustion of cane sugar is `-1349kcal`, then his daily comsumption of sugar is `:`

A

728 g

B

0.728 g

C

342 g

D

0.342 g

Text Solution

Verified by Experts

The correct Answer is:
A

1 mole of` C_(12)H_(22)O_(11)=342 g `
`therefore` For 342 g E `-=` 1349 kcal `therefore` But E `-=` 2870. kcal
`therefore` Amount of sugar neded `=(2870xx342)/(1349) = 727.6` g
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