The ethalpy of combustion of sucrose `(C_(12)H_(22)O_(11))` is 1350 kcal . Amount of heat liberated when 342 gm of sucrose is burnt is

Options

A. 13.5 k cal
B. `13.5 xx 10^2 k cal `
C. `1.35 xx 10^4 k cal`
D. `1.35 k cal `

Answer

B

Explanation

Molar mass of sucrose `(C_(12)H_(222)O_11)) = 342 therefore`
Number of moles`= ("Mass in gms" )/("Molecular mass") = 342/342 = 1`
`therefore ` Heat of liberated `= 1xx1350 = 1350` kcal