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H2(g) +Cl(2)=2HCl(g), Delta H(298 K) =-9...

`H_2(g) +Cl_(2)=2HCl(g), Delta H(298 K) =-92.01 kJ.`
For this reaction `Delta U` is equal to

A

`-92.06 +2 xx 10^(-3) xx 298 xx 2 J`

B

`-92.06 + 2 xx 298 kJ`

C

`-92.06 -2 xx 298 xx 4 kJ`

D

`-92.06 kJ`

Text Solution

Verified by Experts

The correct Answer is:
D
`Deltan=0` `therefore = DeltaH=DeltaU`
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