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Given that standard heat enthalpy of CH(...

Given that standard heat enthalpy of `CH_(4), C_(2)H_(4)` and `C_(3)H_(8)` are -17.9, 12.5, -24.8 Kcal/mol. The `Delta H` for `CH_(4)+C_(2)Hrarr C_(3)H_(8)` is :

A

`-55.2` kcal

B

`-30.2` kcal

C

55.2 kcal

D

`-19.4 ` kcal

Text Solution

Verified by Experts

The correct Answer is:
D
`DeltaH = [H_(C_(3)H_(8))]-[H_(CH_4)+H_(C_(2)H_(4))]`
= (-24.8)-(-17.9+12.5)= -24.8 + 17.9 - 12.5
- 19.4 kcal
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