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The enthalpy of formation of HBr, H atom...

The enthalpy of formation of HBr, H atom and Br atoms are - 36.2, 215 and 94 kJ `mol^-1` respectively. The bond energy of HBr bond would be

A

`272.8 kJ " mole "^(-1)`

B

`345.2 kJ mol^-1`

C

`581.8 kJ mol^-1`

D

618. kJ mol

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The correct Answer is:
B
Given
`(1//2) H_(2(g)) + (1//2) Br_(2(g)) to H Br , Delta H = -36.2 k J mol^(-1) " " … (i)`
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