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The oxidation state of oxygen in O2[PtF6...

The oxidation state of oxygen in `O_2[PtF_6]` is

A

Zero

B

`+1//2`

C

`+1`

D

`-1//2`

Text Solution

Verified by Experts

The correct Answer is:
B
`O_(2)[PtF_(6)]` can be written as `O_(2)^(+)[PtF_(6)]^(-)`. The oxidation state of Pt in this compound is `+5`. Let x=oxidation state of oxygen. Here oxidation state of F=`-1`.
`2x+5+6(-1)=0`
`x=+1//2`
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