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The ion [Co(NH(3))(6)]^(+) is octahedral...

The ion `[Co(NH_(3))_(6)]^(+)` is octahedral and high spin. This complex is

A

paramagnetic, with 1 unpaired electrons

B

paramagnetic, with 3 unpaired electrons

C

paramagnetic, with 4 unpaired electrons

D

paramagnetic, with 5 unpaired electrons

Text Solution

Verified by Experts

The correct Answer is:
B

The complex ion is high spin, i.e., the electrons are arranged so that they remain unpaired as much as possible. This can be possible, if the d-orbitals involved are from higher energy shell than from ns and np-orbitals. In otherwords, in a high spin complex, (n-1)d-orbitals are not involved in the hybridization.

High spin complexes always have more magnetic moment than low spin complexes. On the other hand, `[Co(CN)_(6)]^(3-)` is referred to as low spin complex, because the electrons are arranged so that they remain paired as much as p[ossible. In this case, d-orbitals involved in hybridization scheme are from lower energy shell than ns and np-orbitals.
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Assertion: Complex ion [Co(NH_(3))_(6)]^(2+) is readily oxidized to [Co(NH_(3))_(6)]^(3+) Reason: Unpaired electron in complex ion [Co(NH_(3))_(6)]^(2+) is present in 4p orbital.