Which of the following facts about the complex `[Cr(NH_(3))_(6)]Cl_(3)` is wrong ?

Options

A. The complex involves `d^(2)sp^(3)` hybridisation and is octahedral in shape
B. The complex is paramagnetic
C. The complex is an outer orbital complex
D. The complex gives while precipitate with silver nitrate

Answer

C

Explanation

In case of `d^(3)` configuration, the number of unpaired electrons remains 3 whether the ligand is strong field or weak filed. The hybridisation scheme can be shown as follow `[Cr(NH_(3))_(3)]^(3+)`=

Hence the complex is inner orbital complex as it involves (n-1)d orbitals hybridisation, `3.93=sqrt(n(n+2))`, so n=3 (here n is number of unpaired electron (s)).