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NIKITA PUBLICATION-DIFFERENTIATION -MCQ
- If y=cos^(-1) (log(2)x),"then "dy/dx=
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- If y=tan^(-1) (3x^(2)+2),"then "dy/dx=
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- At x=0," if " (d)/(dx) (tan^(-1) (a+bx))=1," then "a^(6)-b^(3)+1=
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- If y=cot^(-1) ((1)/(sqrtx)),"then "dy/dx=
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- If y="cosec"^(-1) (2x+1),"then "dy/dx=
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- If y=(tan^(-1) x)^(4/3),"then "dy/dx=
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- If y=sin(2 cos^(-1)x),"then " dy/dx=
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- If y="cosec"(3 tan^(-1) x),"then "dy/dx=
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- (d)/(dx) (cos (sec^(-1) ((x)/(8)))=
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- If y=sin^(-1) (cos 3x),"then "dy/dx=
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- If y=cos^(-1) (cos x),"then " (dy)/(dx) is
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- If y=cos^(-1) (sin x^(2)),"then " (dy)/(dx)=
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- If y=sin^(-1) x+cos^(-1) x,"then "dy/dx=
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- If y="cosec"^(-1)((x^(2)+1)/(x^(2)-1))+cos^(-1) ((x^(2)-1)/(x^(2)+1)),...
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- If y=sec^(-1) ((sqrtx-1)/(x+sqrtx))+sin^(-1) ((x+sqrtx)/(sqrtx-1))," t...
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- If y=tan^(-1) sqrt(x^(2)+y^(2))+cot^(-1) sqrt(x^(2)+y^(2)),"then " dy/...
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- If xy = tan^(-1) (xy) + cot^(-1) (xy), " then" (dy)/(dx) is equal to
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- If y=tan^(-1)(1+2x)+tan^(-1)(1-2x),"then "dy/dx=
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- If y=10^(cot^(-1))+10^(tan^(-1)),"then "(dy)/(dx)=
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- If y=sqrtx "cosec"^(-1) ((1)/(4x)),"then "dy/dx=
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