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NIKITA PUBLICATION-DIFFERENTIATION -MCQ
- If y=(3a^(2)x-x^(3))/(a^(3)-3ax^(2)) then find (dy)/(dx)
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- If y=tan n^(-1) ((sqrtx(3-x))/( 1-3x) ) ,then (dy)/(dx) =
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- If y=tan^(-1)sqrt((1-x)/(1+x)), then find (dy)/(dx) when -1 lt x lt 1.
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- If y=tan ^(-1) sqrt(( a-x)/( a+x)) ,then (dy)/(dx) =
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- If y=tan ^(-1) (sqrt( 1+x^(2)) +x ),then (dy)/(dx) =
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- If y=tan ^(-1) (sqrt( 1+x^(2))-x),then ( dy)/(dx)=
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- 11I fy=tan^(- 1)[(sqrt(1+a^2x^2)-1)/(a x)],t h e n f i n d(dy)/(dx)
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- If y = tan^(-1) {(sqrt(1 + x^(2)) -1)/(x)} " then " (dy)/(dx)= ?
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- If y=tan ^(-1) (sqrt( 1+x^(2))-x),then ( dy)/(dx)=
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- If y=cot ^(-1) sqrt(( x^(2) +a^(2)+x)/( sqrt( x^(2)+a^(2) -x)) ) ,the...
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- (dy)/(dx)ify=cot^(- 1)((x^x-x^x)/2)a tx=1
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- If y=tan ^(-1) ((6x )/( 1-8x^(2))),then (dy)/(dx)=
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- tan^(-1)((7x)/(1-12x^(2)))
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- If y=tan ^(-1) ((a+x) /(1-ax) ),then (dy)/(dx) =
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- If y=tan ^(-1) ((log (ex))/( log ((e)/( x)))) ,then (dy)/(dx) =
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- If y=tan^(-1) ((1+x)/(1-x)) then (dy)/(dx)=
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- tan^(-1)((5x+1)/(3-x-6x^(2)))
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- If y= tan ^(-1) ((5ax )/( a^(2) - 6x^(2))),then (dy)/(dx) =
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- tan^(-1)((a+btanx)/(b-atanx))
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- If y=tan ^(-1) ((a-x) /(1+x^(2))),then (dy)/(dx) =
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