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If the inverse function of y=f(x) is x=g...

If the inverse function of` y=f(x)` is` x=g(y) `and `f'(x) = 1/(1+x^2)` , then prove that, `g'(x)=1 + [g(x)]^2`.

A

` ( 1+f(x))^(2)`

B

` ( 1+g(x))^(2)`

C

` 1+(f(x))^(2)`

D

` 1+(g(x))^(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
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