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If x=a sin theta ,y =bcos theta,then (d...

If ` x=a sin theta ,y =bcos theta,then (d^(2)y)/(dx^(2))=`

A

` (-b)/( a^(2))sec^(2) theta`

B

` (-b)/( a)sec ^(2)theta `

C

` (a)/(b) sec ^(2) theta `

D

` (-b^(2))/( a^(2))sec ^(3) theta `

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A
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