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If int(cos4x+1)/(cotx-tanx)dx=kcos4x+c, ...

If `int(cos4x+1)/(cotx-tanx)dx=kcos4x+c`, then k= (A) `-1/4` (B) `-1/2` (C) `-1/8` (D) none of these

A

`(-cos4x)/(8)+c`

B

`(cos4x)/(8)+c`

C

`(-cos4x)/(4)+c`

D

`(cos4x)/(4)+c`

Text Solution

Verified by Experts

The correct Answer is:
A
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