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int(cotx)/(cosecx-cotx)dx=...

`int(cotx)/(cosecx-cotx)dx=`

A

`cosecx-cotx-x+c`

B

`cosecx+cotx-x+c`

C

`-cosecx-cotx-x+c`

D

`cosecx-cotx+x+c`

Text Solution

Verified by Experts

The correct Answer is:
C
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