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int(secx cosec x)/(log(cotx))dx=...

`int(secx cosec x)/(log(cotx))dx=`

A

`-log(cotx)+c`

B

`-log|log(cotx)|+c`

C

`cosec^2x log|log(cotx)|+c`

D

`cosec^2xlog(cotx)+c`

Text Solution

Verified by Experts

The correct Answer is:
B
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Knowledge Check

  • int secx cosec x log(tanx)dx=

    A
    `log[log(tanx)]+c`
    B
    `(1)/(2)[log(tanx)]^(2)+c`
    C
    `log(sec x cos x)+c`
    D
    `(1)/(2)[tan(logx)]^(2)+c`

  • int((secx+ "cosec x")(secx- "cosec x"))/(tanx +cotx)dx=

    A
    `(log|tanx+cotx|)^2+c`
    B
    `-(log|tanx+cotx|)^2+c`
    C
    `log|tanx+cotx|+c`
    D
    `-log|tanx+cotx|+c`

  • int(secx)/(log(secx+tanx))dx=

    A
    `-log|secx+tanx|+c`
    B
    `log|secx+tanx|+c`
    C
    `-log|log(secx+tanx)|+c`
    D
    `log|log(secx+tanx)|+c`

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