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int(cos2x-cos2alpha)/(cosx-cosalpha)dx...

`int(cos2x-cos2alpha)/(cosx-cosalpha)dx`

A

`sec alpha sinx-2cosalphalog|secx+tanx|+c`

B

`sec alpha sinx+2cosalphalog|secx+tanx|+c`

C

`cos alpha sinx-2cosalphalog|secx+tanx|+c`

D

`cos alpha sinx+2cosalphalog|secx+tanx|+c`

Text Solution

Verified by Experts

The correct Answer is:
A
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