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intdx/(sinxcos^2x)...

`intdx/(sinxcos^2x)`

A

`secx-log|cosecx-cotx|+c`

B

`secx+log|cosecx-cotx|+c`

C

`-cosecx-log|cosecx-cotx|+c`

D

`-cosecx+log|cosecx-cotx|+c`

Text Solution

Verified by Experts

The correct Answer is:
B
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