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NIKITA PUBLICATION-INTEGRATION -MULTIPLE CHOICE QUESTIONS
- int sin(2x)/(sin(x+pi/6)sin(x-pi/6))dx
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- If int(sinx)/(cos(x-a))dx=kx+n.log[sec(x-a)]+p, then (k, n)-=
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- Evaluate the following integrals: int(cosx)/(cos(x+alpha))dx
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- int(sinx)/(sin(c-alpha)) dx = ?
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- int(cos(x-a))/(sin(x+a))dx=
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- Evaluate : int(sin(x-a))/(sin(x+a))dx
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- int(cos(x-a))/(sin(x+b))dx=
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- int(sin(x+a))/(cos(x-b))dx=
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- int(sin(x+a))/(cos(x-a))dx=
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- int(sin(x+a)-sin(x-a))/(sin(x+a)+sin(x-a))dx=
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- int(sinx+cosx)/(sin(x+alpha))dx=
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- int (dx)/(sin(x-a)sin(x-b)
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- int(dx)/(sin(x+a)sin(x+b))=
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- Evaluate: int1/(cos(x-a)cos(x-b))\ dx
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- Evaluate: (i) int(cos2x+x+1)/(x^2+sin2x+2x)\ dx (ii) int1/(cos(x+a)cos...
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- int(dx)/(cos(x-a)sin(x-b))=
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- int 1/(sin(x-a) cos(x-b)) dx=
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- int 1/(1+tanx) dx
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- int(dx)/((1-cotx))=?
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- (1)/(2+3tanx)
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