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NIKITA PUBLICATION-INTEGRATION -MULTIPLE CHOICE QUESTIONS
- (1)/(2+3tanx)
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- int(sinx+cosx)/(3sinx+4cosx)dx=
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- Evaluate: int(2sinx+3cosx)/(3sinx+4cosx)\ dx
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- int(4sinx-38cosx)/(5sinx-11cosx)dx=
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- int(3e^x+4)/(2e^x-8)dx=
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- int(4e^x+4)/(2e^x-8)dx=
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- int(3e^(2x)+5)/(4e^(2x)-5)dx=
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- int(20-12e^x)/(3e^x-4)dx=
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- int(dx)/(sqrt(x)+root(3)x)
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- int(sqrtx)/(sqrt(x)+root(3)x)dx=
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- int(sqrtx)/(1+root4(x^3))dx=
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- int(dx)/(sqrt(x+2)+root6(x+2))=
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- int(dx)/[(3x+2]^((2)/(3))+(3x+2)^((4)/(5)))=
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- int(dx)/(x^2+8)=
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- int(dx)/(alpha^2x^2+beta^2)=
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- int(dx)/(5x^2+7)=
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- int(1)/(16x^(2)+9)dx is equal to
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- int(sqrtx)/(1+x)dx=
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- int(sinx)/(1+cos^2x)dx=
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- int(dx)/(sin^2x+cos^2x+5)=
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