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NIKITA PUBLICATION-INTEGRATION -MULTIPLE CHOICE QUESTIONS
- int(dx)/(5x^2+7)=
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- int(1)/(16x^(2)+9)dx is equal to
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- int(sqrtx)/(1+x)dx=
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- int(sinx)/(1+cos^2x)dx=
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- int(dx)/(sin^2x+cos^2x+5)=
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- int(dx)/(sqrt(1-x^2)(9+(sin^(-1)x)^2))=
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- int(dx)/(e^(3x)+e^(-3x))=
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- (1)/(ae^(x)+be^(-x))
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- int(dx)/(a^2e^x+b^2e^(-x))=
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- int(dx)/((4x^(2)-1))=?
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- int(dx)/(9x^2-8)=
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- int(x^3)/(16x^8-25)dx=
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- int(dx)/(a^2-b^2x^2)=
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- int(dx)/(8-7x^2)=
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- int(secx tanx)/(9-16 tan^2x)dx=
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- int(1+tan^2x)/(1-tan^2x)dx
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- int(dx)/(sqrt(a^2-b^2x^2))=
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- int(1/sqrt(9-25x^2)) dx
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- If int(1)/(sqrt(9-16x^(2)))dx=alphasin^(-1)(betax)+c, then alpha+(1)/(...
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- Evaluate: intsqrt((1-x)/(1+x))\ dx
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