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int[(1)/(logx)-(1)/((logx)^(2))]dx=...

`int[(1)/(logx)-(1)/((logx)^(2))]dx=`

A

`(1)/(logx)+c`

B

`(x)/(logx)+c`

C

`(x)/(logx)^2+c`

D

`(1)/(xlogx)+c`

Text Solution

Verified by Experts

The correct Answer is:
B
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