Two equal sides of an isosceles triangle are given by `7x-y+3=0` and `x+y=3`, and its third side passes through the point `(1,-10)`. Find the equation of the third side.

The equation of two equal sides of an isosceles triangle are 7x - y + 3 = 0 and x + y - 3 = 0 and its third side is passes through the point (1, - 10). The equation of the third side is

Two sides of an isosceles triangle are given by the equations 7x-y+3=0 and x+y-3=0 and its third side passes through the point (1,-1)dot Determine the equation of the third side.

Two equal sides of an isosceles triangle are 7x-y+3=0,x-y-3=0 and its third side passes through the point (1,0) the equation of the third side is (A) 3x+y+7=0 (B) x-3y+29=0 (C) 3x+y+3=0( D) 3x+y-3=0

Two equal sides of an isosceles triangle are given by equations 7x - y + 3 = 0 and x + y - 3 = 0 . It's third side passes through the point (1, -10) . Determine the equation of the third side. (A) x - 3y - 31 = 0 (B) 3x + y + 7 = 0 (C) Both (A), (B) (D) Neither (A), nor (B)

Equation of two equal sides of a triangle are the lines 7x+3y-20=0 and 3x+7y-20=0 and the third side passes through the point (-3,, 3), then the equation of the third side can be -

Two equal sides of an isosceles triangle are given by the equations 7x-y+3=0 and x+y-3=0. The slope of the third side is

The equation of the side AB and AC of a triangle ABC are 3x+4y+9 and 4x-3y+16=0 respectively. The third side passes through the point D(5, 2) such that BD:DC=4:5 . Find the equation of the third side.