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If the equation of the locus of a point ...

If the equation of the locus of a point equidistant from the points `(a_1, b_1)` and `(a_2, b_2)` is `(a_1-a_2)x+(b_1-b_2)y+c=0` , then the value of `c` is `a a2-a2 2+b1 2-b2 2` `sqrt(a1 2+b1 2-a2 2-b2 2)` `1/2(a1 2+a2 2+b1 2+b2 2)` `1/2(a2 2+b2 2-a1 2-b1 2)`

A

`a_(1)^(2)-a_(2)^(2)+b_(1)^(2)-b_(2)^(2)`

B

`sqrt((a_(1)^(2)+b_(1)^(2)-a_(2)^(2)-b_(2)^(2)))`

C

`1/2(a_(1)^(2)+a_(2)^(2)+b_(1)^(2)+b_(2)^(2))`

D

`1/2(a_(2)^(2)+b_(2)^(2)-a_(1)^(2)-b_(1)^(2))`

Text Solution

Verified by Experts

The correct Answer is:
D
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