Home
Class 12
MATHS
In a triangle, ABC, the equation of the ...

In a triangle, ABC, the equation of the perpendicular bisector of AC is `3x - 2y + 8 = 0`. If the coordinates of the points A and B are `(1, -1) & (3, 1)` respectively, then the equation of the line BC & the centre of the circum-circle of the triangle ABC will be

Text Solution

Verified by Experts

The correct Answer is:
`4x-y+6=0,(-4/5,14/5)`
Promotional Banner

Topper's Solved these Questions

  • THE STRAIGHT LINES

    ARIHANT MATHS|Exercise Exercise For Session 6|12 Videos

  • THE STRAIGHT LINES

    ARIHANT MATHS|Exercise Exercise (Single Option Correct Type Questions)|28 Videos

  • THE STRAIGHT LINES

    ARIHANT MATHS|Exercise Exercise For Session 4|15 Videos

  • SETS, RELATIONS AND FUNCTIONS

    ARIHANT MATHS|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|12 Videos

  • THEORY OF EQUATIONS

    ARIHANT MATHS|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|35 Videos

Similar Questions

Explore conceptually related problems

If the coordinates of the vertices of triangle ABC are (-1,6),(-3,-9) and (5,-8) respectively,then find the equation of the median through C.

The equations of the perpendicular bisectors of the sides AB and AC of triangle ABC are x-y+5=0 and x+2y=0, respectively.If the point A is (1,-2) ,then find the equation of the line BC .

The equations of perpendicular bisectors of the sides AB and AC of a DeltaABC are x - y + 5 = 0 and x+2y = 0 , respectively. If the point A is (1, - 2) the equation of the line BC is

In an isosceles triangle ABC, the coordinates of the points B and C on the base BC are respectively (1,2) and (2.1). If the equation of the line AB is y=2x, then the equation of the line AC is

The equations of the perpendicular bisector of the sides AB and perpendicular bisector of the sides AB and AC of a /_ABC are x-y+5=0 and x+2y=0 respectively,if the point Ais (1,-2), then the equation ofthe line BC is

The equation of the perpendicular bisector of the side AB of a triangle ABC is x-y+5=0 . If the point A is (1,2) , find the co-ordinates of the point B .

The coordinates of angular point of a Delta ABC are A(0,1), B(2,0) and C(-1,-2). Find the equation of side AB of the triangle.

In a triangle ABC,A(1,3) and perpendicular bisector of AB is y=x and orthocentre of triangle ABC is (3,1), then locus of vertex C is