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Statement I : The lines x(a+2b) +y(a+3b)...

Statement I : The lines `x(a+2b) +y(a+3b)=a+b ` are concurrent at the point `(2,-1)`
Statement II : The lines `x+y -1 =0 and 2x + 3y -1 = 0 ` intersect at the point `(2,-1)`

A

Statement I is true ,statement II is true , statement II is a correct explanation for statement I

B

Statement I is true ,statement II is true statement II is not a correct explanation for statement I

C

Statement I is true ,statement II is false

D

Statement I is false ,statement II is true

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • The lines 2x + y -1=0 , ax+ 3y-3=0 and 3x + 2y -2=0 are concurrent for -

    A
    All a
    B
    a= 4 only
    C
    `1 le a le 3`
    D
    `a lt 0` only

  • The point of intersection of the lines x/ay/b =1 and x/b +y/a =1 lines on the line

    A
    `x-y =0`
    B
    `(x+y) (a+b) =2ab`
    C
    `(lx+ my) (a+b) =(l+m) ab`
    D
    All of these

  • The tangents to the curve y = (x - 2)^(2) - 1 at its points of intersectio with the line x - y = 3, intersect at the point

    A
    `((5)/(2), 1)`
    B
    `(-(5)/(2), -1)`
    C
    `((5)/(2), -1)`
    D
    `(-(5)/(2), 1)`

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