Consider the relation `4l^(2)-5m^(2)+6l+1=0` , where `l,m in R`
The number of tangents which can be drawn from the point (2,-3) to the above fixed circle are

Options

A. `((1)/(2),(5)/(2))`
B. `((1)/(3),(4)/(3))`
C. `(-(1)/(2),(3)/(2))`
D. `((1)/(2),(5)/(2))`

Answer

`:.` Fixed piont is `((1)/(2),(-5)/(2))`