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ABCD is a square in first quadrant whose...

`ABCD` is a square in first quadrant whose side is a, taking `AB and AD` as axes, prove that the equation to the circle circumscribing the square is `x^2+ y^2= a(x + y)`.

A

`x^(2)+y^(2)+ax-ay=0`

B

`x^(2)+y^(2)-ax+ay=0`

C

`x^(2)+y^(2)-ax-ay=0`

D

`x^(2)+y^(2)+ax-ay=0`

Text Solution

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The correct Answer is:
C
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