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The point of tangency of the circles x^2...

The point of tangency of the circles `x^2+ y^2 - 2x-4y = 0 and x^2 + y^2-8y -4 = 0`, is

A

touch each other intermally

B

touch each other externally

C

cuts each other at two points

D

None of these

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • Two circles x^(2) + y^(2) - 2x - 4y = 0 and x^(2) + y^(2) - 8y - 4 = 0

    A
    touch externally
    B
    touch internally
    C
    are orthogonal
    D
    do not touch

  • The circles x^(2)+y^(2)-2x-4y+1=0 and x^(2)+y^(2)+4y-1 =0

    A
    touch internally
    B
    touch externally
    C
    have `3x+4y-1=0` as the common tangent at the point of contact.
    D
    have `3x+4y+1=0` as the common tangent at the point of contact.

  • Which of the following is a point on the common chord of the circles x^2+y^2+2x-3y+6=0 and x^2+y^2+x-8y-13=0 ?

    A
    (1,-2)
    B
    (1,4)
    C
    (1,2)
    D
    (1,-4)

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