If the circle x^2+y^2 +4x+22y + c = 0 bi...

If the circle `x^2+y^2 +4x+22y + c = 0` bisects the circumference of the circle `x^2 + y^2-2x + 8y-d = 0`,then `(c+d)`is equal to

A

40

B

50

C

60

D

70

Verified by Experts

The correct Answer is:

B

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