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Two circle x^2+y^2=6 and x^2+y^2-6x+8=0 ...

Two circle `x^2+y^2=6` and `x^2+y^2-6x+8=0` are given. Then the equation of the circle through their points of intersection and the point (1, 1) is `x^2+y^2-6x+4=0` `x^2+y^2-3x+1=0` `x^2+y^2-4y+2=0` none of these

A

`x^(2)+y^(2)-6x+4=0`

B

`x^(2)+y^(2)-3x+1=0`

C

`x^(2)+y^(2)-4x+2=0`

D

`x^(2)+y^(2)-2x+1=0`

Text Solution

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The correct Answer is:
B
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ARIHANT MATHS-CIRCLE -Exercise For Session 6
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  7. The two circles x^2+ y^2=r^2 and x^2+y^2-10x +16=0 intersect at two d...

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  8. If the circle x^2+y^2 +4x+22y + c = 0 bisects the circumference of the...

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  9. Two circle x^2+y^2=6 and x^2+y^2-6x+8=0 are given. Then the equation o...

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  11. The equation of the diameter of the circle 3(x^(2)+y^(2))-2x+6x-9-0 wh...

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  12. consider two curves ax^2+4xy+2y^2+x+y+5=0 and ax^2+6xy+5y^2+2x+3y+8=0 ...

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  13. Find the equation of the circle passing throught (1,1) and the points ...

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  14. Show that the common chord of the circles x^(2)+y^(2)-6x-4y+9=0andx^(2...

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  15. Prove that the circles x^(2)+y^(2)+2ax+2ax+2by=0 and x^(2)+y^(2)+2a(1)...

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