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From the point A(0,3) on the circle x^2 ...

From the point A(0,3) on the circle `x^2 +4x + (y-3)^2 = 0 ` a chord AB is drawn to a point such that AM = 2AB. The equation of the locus of M is :-

A

`x^(2)+6x+(y-2)^(2)=0`

B

`x^(2)+8x+(y-3)^(2)=0`

C

`x^(2)+y^(2)+8x-6y+9=0`

D

`x^(2)+y^(2)+6x-4y+4=0`

Text Solution

Verified by Experts

The correct Answer is:
B, C
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