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Find the angle between the pair of tange...

Find the angle between the pair of tangents from the point (1,2) to the ellipse `3x^2+2y^2=5.`

A

`tan^(-1)((12)/5)`

B

`tan^(-1)((6)/sqrt5)`

C

`tan^(-1)((12)/(sqrt5))`

D

`tan^(-1)(sqrt5)`

Text Solution

Verified by Experts

The correct Answer is:
C
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Knowledge Check

  • The angle between the pair of tangents drawn from the point (2,4) to the circle x^(2)+y^(2)=4 is

    A
    `tan^(-1)(3//8)`
    B
    `tan^(-1)(4//3)`
    C
    `90^(@)`
    D
    none

  • If pair of tangents drawn to the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 . From the point P(1, sqrt(3)) are perpendicular to each other , then the angle between the pair of tangents drawn from the point Q(3,2) at the curve (x^(2))/(2a^(2)+b^(2))+(y^(2))/(2a^(2)+b^(2))=1 can be

    A
    `(pi)/(3)`
    B
    `(2pi)/(3)`
    C
    acute angle
    D
    obtuse angle

  • Angle between the tangents drawn from point (4, 5) to the ellipse x^2/16 +y^2/25 =1 is

    A
    `pi/3`
    B
    `5pi/6`
    C
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    D
    `pi/2`

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