intsqrt[tanx].dx...

`intsqrt[tanx].dx`

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The correct Answer is:

`1/sqrt(2)[tan^(-1)((t-1//t)/(sqrt(2)))+1/2 log ((t+1/t-sqrt(2))/(t+1/t+sqrt(2)))]+C " " `[(where `t=sqrt(tanx)`)]

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intsqrt[tanx].dx
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