Home
Class 12
MATHS
If the length of latusrectum of ellipse ...

If the length of latusrectum of ellipse `E_(1):4(x+y+1)^(2)+2(x-y+3)^(2)=8` and `E_(2)=(x^2)/(p)+(y^2)/(p^2)=1, (0ltplt1)` are equal , then area of ellipse `E_(2)`, is

A

`pi/2`

B

`pi/(sqrt2)`

C

`pi/(2sqrt(2))`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • AREA OF BOUNDED REGIONS

    ARIHANT MATHS|Exercise Exercise (More Than One Correct Option Type Questions)|5 Videos
  • AREA OF BOUNDED REGIONS

    ARIHANT MATHS|Exercise Exercise (Statement I And Ii Type Questions)|5 Videos
  • AREA OF BOUNDED REGIONS

    ARIHANT MATHS|Exercise Exercise For Session 2|20 Videos
  • BIONOMIAL THEOREM

    ARIHANT MATHS|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|21 Videos

Similar Questions

Explore conceptually related problems

The length of the latusrectum of the ellipse 3x^(2)+y^(2)=12 is

the length of the latusrectum of the ellipse 3x^(2) + y^(2) = 12 . Is

the length of the latusrectum of the ellipse (x^(2))/(36)+(y^(2))/(49)=1 , is

The length of the Latusrectum of the ellipse ((x-alpha)^(2))/(a^(2))+((y-beta)^(2))/(b^(2))=1 (a

Question Stimulus :- The length of latusrectum of the ellipse 9x^2+4y^2=1 is-

Find the area of ellipse x^(2)/1 + y^(2)/4 = 1.

Area of quadrilateral formed by common tangents to ellipses E_(1):(x^(2))/(16)+(y^(2))/(9)=1 and E_(2):(x^(2))/(9)+(y^(2))/(16)=1 is

Let the equations of two ellipses be E_(1)=(x^(2))/(3)+(y^(2))/(2)=1 and (x^(2))/(16)+(y^(2))/(b^(2))=1. If the product of their eccentricities is (1)/(2), then the length of the minor axis of ellipse E_(2) is

The eccentricity of the ellipse x^(2)+4y^(2)+8y-2x+1=0 , is

If e_(1) and e_(2) are respectively the eccentricities of the ellipse (x^(2))/(18)+(y^(2))/(4)=1 and the hyperbola (x^(2))/(9)-(y^(2))/(4)=1 , then the relation between e_(1) and e_(2) , is

ARIHANT MATHS-AREA OF BOUNDED REGIONS-Exercise (Single Option Correct Type Questions)
  1. A point P(x,y) moves such that [x+y+1]=[x]. Where [.] denotes greatest...

    Text Solution

    |

  2. "If "f: [-1,1]rarr[-(1)/(2),(1)/(2)],f(x)=(x)/(1+x^(2)), then find the...

    Text Solution

    |

  3. If the length of latusrectum of ellipse E(1):4(x+y+1)^(2)+2(x-y+3)^(2)...

    Text Solution

    |

  4. The area of bounded by the curve 4|x-2017^(2017)|+5|y-2017^(2017)|larr...

    Text Solution

    |

  5. If the area bounded by the corve y=x^(2)+1, y=x and the pair of lines ...

    Text Solution

    |

  6. Suppose y=f(x) and y=g(x) are two continuous functiond whose graphs in...

    Text Solution

    |

  7. Let 'a' be a positive constant number. Consider two curves C1: y=e^x...

    Text Solution

    |

  8. 3 point O(0,0),P(a,a^2),Q(-b,b^2)(agt0,bgt0) are on the parabola y=x^2...

    Text Solution

    |

  9. Area enclosed by the graph of the function y= In^2x-1 lying in the 4...

    Text Solution

    |

  10. The area bounded by y = 2-|2-x| and y=3/|x| is

    Text Solution

    |

  11. Suppose g(x)=2x+1 and h(x)=4x^(2)+4x+5 and h(x)=(fog)(x). The area enc...

    Text Solution

    |

  12. The area bounded by the curves y=-sqrt(-x) and x=-sqrt(-y) where x,yle...

    Text Solution

    |

  13. y=f(x) is a function which satisfies f(0)=0, f"''(x)=f'(x) and f'(0)=1...

    Text Solution

    |

  14. Aea of the region nclosed between the curves x=y^2-1 and x=|y|sqrt(1-y...

    Text Solution

    |

  15. The area bounded by the curve y=xe^(-x);xy=0and x=c where c is the x-c...

    Text Solution

    |

  16. If (a,0), agt 0, is the point where the curve y=sin 2x-sqrt3 sin x cut...

    Text Solution

    |

  17. The curve y=ax^2+bx +c passes through the point (1,2) and its tangent ...

    Text Solution

    |

  18. A function y=f(x) satisfies the differential equation (dy)/(dx)-y= co...

    Text Solution

    |

  19. If the area bounded between X-axis and the graph of y=6x-3x^2 between ...

    Text Solution

    |

  20. Area bounded by y=f^(-1)(x) and tangent and normal drawn to it at poin...

    Text Solution

    |