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Convert 40^(@)21' into radian measure....

Convert `40^(@)21'` into radian measure.

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To convert \(40^\circ 21'\) into radian measure, we will follow these steps: ### Step 1: Convert minutes to degrees We know that: 1 degree = 60 minutes Thus, to convert 21 minutes into degrees: \[ 21' = \frac{21}{60} \text{ degrees} \] ### Step 2: Add degrees and converted minutes Now, we can express \(40^\circ 21'\) as: \[ 40^\circ + 21' = 40^\circ + \frac{21}{60}^\circ \] ### Step 3: Find a common denominator To add these two terms, we can express \(40^\circ\) in terms of a fraction: \[ 40^\circ = \frac{40 \times 60}{60} = \frac{2400}{60}^\circ \] Now, we can add: \[ \frac{2400}{60}^\circ + \frac{21}{60}^\circ = \frac{2400 + 21}{60}^\circ = \frac{2421}{60}^\circ \] ### Step 4: Convert degrees to radians We know that: \[ 180^\circ = \pi \text{ radians} \] To convert degrees to radians, we use the conversion factor: \[ \text{radians} = \text{degrees} \times \frac{\pi}{180} \] Thus, we can convert \(\frac{2421}{60}^\circ\) to radians: \[ \text{radians} = \frac{2421}{60} \times \frac{\pi}{180} \] ### Step 5: Simplify the expression Now, we simplify: \[ \text{radians} = \frac{2421 \pi}{60 \times 180} \] Calculating \(60 \times 180\): \[ 60 \times 180 = 10800 \] So we have: \[ \text{radians} = \frac{2421 \pi}{10800} \] ### Step 6: Final answer Thus, the final answer in radian measure is: \[ \text{radians} = \frac{2421 \pi}{10800} \] ---
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ARIHANT MATHS-TRIGONOMETRIC FUNCTIONS AND IDENTITIES-Exercise (Questions Asked In Previous 13 Years Exam)
  1. Convert 40^(@)21' into radian measure.

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  2. If alpha and beta are non-zero real number such that 2(cos beta-cos al...

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  3. Let -1/6 < theta < -pi/12 Suppose alpha1 and beta1, are the root...

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  4. The value of sum(k=1)^(13) (1)/(sin(pi/4 + ((k-1)pi)/(6))sin(pi/4 + (k...

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  5. Let f : (-1, 1) -> R be such that f(cos4theta) = 2/(2-sec^2theta for t...

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  6. The number of all possible values of theta, where 0 lt theta lt pi, f...

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  7. For 0 lt theta lt pi/2, the solution (s) of sum(m=1)^(6) cosec (the...

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  8. If sin^ 4 x/2+cos^4 x/3 =1/5 then

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  9. Let theta in (0,pi/4) and t1=(tan theta)^(tan theta), t2=(tan theta)6(...

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  10. cos(alpha-beta)=1a n dcos(alpha+beta)=l/e , where alpha,betamu in [-pi...

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  11. If 5(tan^2x - cos^2x)=2cos 2x + 9, then the value of cos4x is

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  12. Let fk(x) = 1/k(sin^k x + cos^k x) where x in RR and k gt= 1. Then f4(...

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  13. The expression (tanA)/(1-cotA)+(cotA)/(1-tanA) can be written as (1) s...

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  14. If a Delta PQR " if" 3 sin P + 4 cos Q = 6 and 4 sin Q + 3 cos P =1 , ...

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  15. If A = sin^2x + cos^4 x, then for all real x :

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  16. Let cos (alpha+beta) = 4/5 and sin(alpha-beta)=5/13 where 0<= alpha,...

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  17. If cosalpha+cosbeta+cosgamma=0=sinalpha+sinbeta+singamma, then which...

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  18. A triangular park is enclosed on two sides by a fence and on the third...

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  19. If 0 lt x lt pi and cos x + sin x = 1/2, then tan x is

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  20. In Delta PQR , /R=pi/4, tan(P/3), tan(Q/3) are the roots of the equati...

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