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x/acostheta+y/bsintheta=1, x/asintheta-y...

`x/acostheta+y/bsintheta=1, x/asintheta-y/bcostheta=1` then `x^2/a^2+y^2/b^2=`

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The correct Answer is:
`(x^(2))/(a^(2))+(y^(2))/(b^(2))=2`
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