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If 3sinbeta=sin(2alpha+beta) then...

If `3sinbeta=sin(2alpha+beta)` then

A

`[cot alpha + cot (alpha+beta)] [ cot beta-3 cot (2 alpha + beta)]=6`

B

`sin beta= cos (alpha+beta) sin alpha `

C

`2 sin beta= sin (alpha + beta ) cos alpha`

D

`tan ( alpha + beta) = 2 tan alpha`

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The correct Answer is:
A, B, C, D
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