A pyramid with vertex at point P has a regular hexagonal base ABCDEF. Position vectors of points A and B are `hati and hati+ 2hatj`, respectively. The centre of the base has the position vector `hati+hatj+sqrt3hatk`.
Altitude drawn from P on the base meets the diagonal AD at point G. Find all possible vectors of G. It is given that the volume of the pyramid is `6sqrt3` cubic units and AP is 5 units.

A pyramid with vertex at point P has a regular hexagonal base A B C D E F , Positive vector of points A and B are hat i and hat i + 2 hat j The centre of base has the position vector hat i+ hat j+sqrt(3) hat kdot Altitude drawn from P on the base meets the diagonal A D at point Gdot find the all possible position vectors of Gdot It is given that the volume of the pyramid is 6sqrt(3) cubic units and A P is 5 units.

The position vectors of points A and B are hati - hatj + 3hatk and 3hati + 3hatj - hatk respectively. The equation of a plane is vecr cdot (5hati + 2hatj - 7hatk)= 0 The points A and B

If the position vectors of the points A and B are hati+3hatj-hatk and 3hati-hatj-3hatk , then what will be the position vector of the mid-point of AB

If the position vectors of the points A and B are hati+3hatj-hatk and 3hati-hatj-3hatk, then what will be the position vectors of the mid point of AB

If position vector of points A,B and C are respectively hati,hatj, and hatk and AB=CX , then position vector of point X is

Two particles of masses 1 kg and 3 kg have position vectors 2hati+3hatj+4hatk and-2hati+3hatj-4hatk respectively. The centre of mass has a position vector

The position vectors of points A,B and C are hati+hatj,hati + 5hatj -hatk and 2hati + 3hatj + 5hatk , respectively the greatest angle of triangle ABC is

The position vectors of the points A,B and C are hati+2hatj-hatk,hati+hatj+hatk and 2hati+3hatj+2hatk , respectively. If A is chosen as the origin, then the position vectors of B and C are

The position vectors of A and B are hati-hatj+2hatk and 3hati-hatj+3hatk . The position vector of the middle points of the line AB is