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10 different vectors are lying on a plan...

10 different vectors are lying on a plane out of which four are parallel with respect to each other. Probability that three vectors chosen from them will satisfy the equation `lambda_1a+lambda_2b+lambda_3c=0,` where `lambda_1, lambda_2 and lambda_3ne=0` is

A

`(.^6C_2times.^4C_1)/(.^(10)C_3)`

B

`((.^6C_3times.^4C_1)+,^6C_3)/(.^(10)C_3)`

C

`((.^6C_3+times.^4C_1)+,^4C_3)/(.^(10)C_3)`

D

`((.^6C_3 +.^4C_1)+,^6C_2times.^4C_1)/(.^(10)C_3)`

Text Solution

Verified by Experts

The correct Answer is:
D
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